Help! Rule Question: multiple enemies

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Re: Help! Rule Question: multiple enemies

Post autor: abubu »

2 rolls was for separating somehow which dies are For 2nd enemy effect. You can make 1 roll with 4 dies but mark somehow 2 dies to chose higher result.

Wy 4? To follow both card effects at the same time.

1st enemy roll 3 dies.
2nd enemy roll 2 dies but finaly is used only 1.
So, using "my method" all card effects are fullfiled.

1 roll. Total 3 dies.

Is that clear? English is not my native language, so maybe i'm not too precise with explanations.


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Re: Help! Rule Question: multiple enemies

Post autor: Rogo »

@abubu you gave me another point of view! Two-headed dragon instructs to roll 2 dice and add them together and then you roll an extra dice (as per pack of wolves) and choose the highest result of
1) the sum of 2 dice
and
2) 3rd dice.


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Re: Help! Rule Question: multiple enemies

Post autor: abubu »

What if you drew two headed dragon and pack of wolves? That can feasibly happen in a game.
I don't have english copy of game so i don't know what is on those cards.

I was answering only to this case:
frolof pisze: piątek 22 sie 2025, 11:47 Draw 2 space.
Let's say you draw an enemy with Strength 3 (enc 2) and it has an special ability to roll 3 dies for its attack roll. (Brutal)

Then you draw another Strength Enemy, (enc 2) and it has a special ability that makes them roll two dice in combat and use the highest result.

These special abilities don't work together when you smash them together. So what would you do? So which goes first? Does the rulebook cover these things?
Dodano po 7 minutach 31 sekundach:
The Dragon rolls 2 dice and adds them together to determine its attack roll. It will remain here until it is killed.
Roll 1 extra die for the Wolves' attack roll and use the highest result. It will remain here until it is killed.
Okay, this case is even easier to explain.

Roll 3 dice and choose the highest combination of the 2 dice.


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Re: Help! Rule Question: multiple enemies

Post autor: frolof »

abubu pisze: niedziela 24 sie 2025, 12:26 Okay, this case is even easier to explain.

Roll 3 dice and choose the highest combination of the 2 dice.
Ok maybe I am missing something, but then you are not adding up 3 dice to their attack score.
And the 2nd enemy is not instructing to roll 1 extra die. It says roll 2 dice and use the highest result.
Wouldn't it be that you roll 4 dice and the 1 lowest dice is the outlier? But neither does it suggest to roll 4 dice.

Another more homebrew solution would be to let "add together to determine attack score" overrules "roll 2 and use the highest result". As it is the stronger variant of the two.
Could explain why flail overrules Warrior's roll 2 dice and use highest result special ability.

Idk I have rubbed my head too long on this matter.

(tbh I have a hard time following you and Rogo's discussion)


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Re: Help! Rule Question: multiple enemies

Post autor: abubu »

First of all .. you gave 2 diferent examlles so i gave two different answers.

Did you read all my previous posts or just last one?


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Re: Help! Rule Question: multiple enemies

Post autor: abubu »

1st case with unnamed enemies.
Enemy with 3 dice roll (sumary result) + enemy with 2 dice roll (only 1 dice with highest result is used). 1 dice is common so this dice should fallow 2nd enemy rule. 2 other dice are for 1st enemy rule. So, best option is to roll 2 dice to follow 2nd enemy rule and pick 1 dice with highest result then roll 2 dice .. now you have 3 dice roll at total. This is both enemy roll result.

2nd case with 2-headed dragon and pack of wolves.
2- headed dragon roll 2 dice. Pack of wolves use extra dice. So roll 3 dice (2+1) and pick 2 highhest results.


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Re: Help! Rule Question: multiple enemies

Post autor: frolof »

abubu pisze: niedziela 24 sie 2025, 12:10 1st enemy roll 3 dies.
2nd enemy roll 2 dies but finaly is used only 1.
So, using "my method" all card effects are fullfiled.
This seems like the most fair resolution to this conundrum. :+1:
Like in the example I wrote,
enemy 1 rolls 3 dice, enemy 2 rolls 2 dice and uses the highest result.

So you'd then roll 3+1 dice and then remove the lowest result.
Then add the result together. Then you have fulfilled both cards really.

Added in 1 minute 37 seconds:
abubu pisze: niedziela 24 sie 2025, 21:28 First of all .. you gave 2 diferent examlles so i gave two different answers.

Did you read all my previous posts or just last one?
Yes, it got confusing. Pardon.

I wrote one to Nemo.

"Draw 2 enemies,
Enemy 1: roll 3 dice and add them together to determine attack score.
Enemy 2: roll two dice and use the highest result.

Both same encounter number. It's a battle.

The question is, which takes priority? Roll 3 die to determine score, or roll two dice and only use 1 highest die result? If so you'd bot fulfill the requirements for Enemy 1."

This has been my latest dilemma.


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Re: Help! Rule Question: multiple enemies

Post autor: abubu »

Case with unnamed enemies and case with 2-headed dragon and pack of wolves are different. In second case i have quoted exact cards text ... pack of wolves use extra dice, so it doesn't matter which pair of dies are compared.

In case of unnamed enemies, the 2nd one have rule to roll 2 dies. So only rhis pair can be compared. Othe two dies from dragon can have lower result, but those dies will stay.
Eg. Roll 2 red dies and 2 green. Those 2 red are additional dies to follow dragon rules. Those 2 green to follow wolves rule. After roll reject lower result from green dies. Sumarize all red dies result and remaining green dice result. This is final enemy roll result.


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